leetcode-study

class Solution:
    def merge(self, intervals: List[List[int]]) -> List[List[int]]:
        """
        Merge all overlapping intervals in a list.

        Parameters:
            intervals (List[List[int]]): A list of intervals, where each interval is represented as [start, end].

        Returns:
            List[List[int]]: A list of merged non-overlapping intervals covering all the intervals in the input.
        """
        # Sort intervals by the start time.
        intervals.sort(key=lambda x: x[0])
        
        # Initialize the list with the first interval.
        merged = [intervals[0]]
        
        # Iterate through each interval starting from the second one.
        for current in intervals[1:]:
            # 'last' holds the last interval in the merged list.
            last = merged[-1]
            # Check if the current interval overlaps with the last interval in merged.
            if current[0] <= last[1]:
                # If there is an overlap, update the end of the last interval with the max end.
                last[1] = max(last[1], current[1])
            else:
                # If there is no overlap, add the current interval to merged.
                merged.append(current)
                
        return merged

Summary of Techniques and Approaches:

These techniques can be identified and applied to various problems that require data grouping, range merging, or interval scheduling, making your solutions not only efficient but also broadly applicable.