leetcode-study

383. Ransom Note

from collections import Counter

class Solution:
    def canConstruct(self, ransomNote: str, magazine: str) -> bool:
        """
        Determine if 'ransomNote' can be constructed from the letters in 'magazine'.
        
        Parameters:
            ransomNote (str): The note that needs to be constructed using letters from 'magazine'.
            magazine (str): The source string containing available letters.
        
        Returns:
            bool: True if 'ransomNote' can be constructed from 'magazine', otherwise False.
        """
        # Create frequency counts for each letter in 'ransomNote' and 'magazine'
        ransom_count = Counter(ransomNote)
        magazine_count = Counter(magazine)
        
        # For each letter required by the ransom note, check if magazine provides enough occurrences
        for letter, count in ransom_count.items():
            # If the count of the letter in the magazine is less than required, return False
            if magazine_count[letter] < count:
                return False
        
        # If all required letters have sufficient occurrences, the note can be constructed
        return True

Summary of Techniques and Approaches:

These techniques can be broadly applied in scenarios that require processing and comparing collections, especially when handling problems around anagrams, frequency analysis, and resource sufficiency.