class Solution:
def reverseWords(self, s: str) -> str:
"""
Reverse the order of words in the input string 's'.
Parameters:
s (str): The input string containing words separated by spaces. This string may include
leading, trailing, or multiple spaces between words.
Returns:
str: A string with the words in reverse order, concatenated by a single space.
"""
# Split 's' into a list of words.
# The split() method without arguments treats consecutive spaces as a single separator.
words = s.split()
# Reverse the list of words in-place.
words.reverse()
# Join the reversed words into one string using a single space as the separator.
return " ".join(words)
Summary of Techniques and Approaches:
Leveraging Built-in String Methods:
The solution uses the split()
method to tokenize the string efficiently by automatically discarding extra spaces. This technique is useful when processing text to isolate meaningful components.
In-place Reversal of a List:
Reversing the list of words using reverse()
is both time-efficient and clean. This approach is applicable in scenarios where the order of elements needs to be manipulated without extra memory overhead.
Concise String Reassembly:
The use of join()
to reassemble the processed list back into a string exemplifies combining methods to produce concise and readable solutions.
General Problem-Solving Tips:
These techniques can be broadly applied to numerous text processing and array manipulation problems.